In a four-point lift with a load of 7750 LBS, sling length 6 ft and vertical distance 4 ft, calculate the sling stress per leg (nearest pound).

Master the XD03.13 Industrial Rigging and Signaling Exam with flashcards and multiple choice questions. Each question includes hints and explanations. Prepare effectively for your exam!

Multiple Choice

In a four-point lift with a load of 7750 LBS, sling length 6 ft and vertical distance 4 ft, calculate the sling stress per leg (nearest pound).

Explanation:
In a four-point lift, the load is shared among the four sling legs, and each sling carries a tension that has a vertical component supporting the weight. The vertical components from all four slings add up to the total load: 4 × T × cos(theta) = W. The angle theta between each sling and the vertical comes from the sling length and the vertical distance: cos(theta) = vertical distance / sling length = 4 ft / 6 ft = 2/3. Solve for the tension per leg: T = W / (4 cos theta) = 7750 / (4 × 2/3) = 7750 / (8/3) = 7750 × 3 / 8 = 2906.25. Rounding to the nearest pound gives 2906 pounds per leg.

In a four-point lift, the load is shared among the four sling legs, and each sling carries a tension that has a vertical component supporting the weight. The vertical components from all four slings add up to the total load: 4 × T × cos(theta) = W. The angle theta between each sling and the vertical comes from the sling length and the vertical distance: cos(theta) = vertical distance / sling length = 4 ft / 6 ft = 2/3. Solve for the tension per leg: T = W / (4 cos theta) = 7750 / (4 × 2/3) = 7750 / (8/3) = 7750 × 3 / 8 = 2906.25. Rounding to the nearest pound gives 2906 pounds per leg.

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